0=3x^2-18x+8

Solution for 0=3x^2-18x+8 equation:

0=3x^2-18x+8

We move all terms to the left:

0-(3x^2-18x+8)=0

We add all the numbers together, and all the variables

-(3x^2-18x+8)=0

We get rid of parentheses

-3x^2+18x-8=0

a = -3; b = 18; c = -8;
Δ = b2-4ac
Δ = 182-4·(-3)·(-8)
Δ = 228
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{228}=\sqrt{4*57}=\sqrt{4}*\sqrt{57}=2\sqrt{57}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{57}}{2*-3}=\frac{-18-2\sqrt{57}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{57}}{2*-3}=\frac{-18+2\sqrt{57}}{-6}
$